The average weight of a package of rolled oats is supposed t

The average weight of a package of rolled oats is supposed to be at least 15 ounces. A sample of 18 packages shows a mean of 14.71 ounces with a standard deviation of 0.41 ounce.

At the 5 percent level of significance, is the true mean smaller than the specification? Clearly state your hypotheses and decision rule.

H0: 15. Reject H0 if tcalc < -1.740

rejected the null hypothesis.

failed to reject the null hypothesis.

(a)

At the 5 percent level of significance, is the true mean smaller than the specification? Clearly state your hypotheses and decision rule.

H1: < 15. Reject H1 if tcalc < -1.740
H1: < 15. Reject H1 if tcalc > -1.740
H0: 18. Reject H0 if tcalc > -1.740

H0: 15. Reject H0 if tcalc < -1.740

(b) If = 0.01, we would have

rejected the null hypothesis.

failed to reject the null hypothesis.

(c) Use Excel to find the p-value. (Round your answer to 4 decimal places.)
  p-value

Solution

The average weight of a package of rolled oats is supposed to be at least 15 ounces. A sample of 18 packages shows a mean of 14.71 ounces with a standard deviation of 0.41 ounce.

(a)

At the 5 percent level of significance, is the true mean smaller than the specification? Clearly state your hypotheses and decision rule.

H1: < 15. Reject H1 if tcalc < -1.740

H1: < 15. Reject H1 if tcalc > -1.740

H0: 18. Reject H0 if tcalc > -1.740

H0: 15. Reject H0 if tcalc < -1.740

(b)

If = 0.01, we would have

rejected the null hypothesis. ( calculated P value 0.004 < 0.01 level)

failed to reject the null hypothesis.

(c)

Use Excel to find the p-value. (Round your answer to 4 decimal places.)

  p-value =0.0040

t Test for Hypothesis of the Mean

Data

Null Hypothesis                m=

15

Level of Significance

0.05

Sample Size

18

Sample Mean

14.71

Sample Standard Deviation

0.41

Intermediate Calculations

Standard Error of the Mean

0.0966

Degrees of Freedom

17

t Test Statistic

-3.0009

Lower-Tail Test

Lower Critical Value

-1.7396

p-Value

0.0040

Reject the null hypothesis

(a)

At the 5 percent level of significance, is the true mean smaller than the specification? Clearly state your hypotheses and decision rule.

H1: < 15. Reject H1 if tcalc < -1.740

H1: < 15. Reject H1 if tcalc > -1.740

H0: 18. Reject H0 if tcalc > -1.740

H0: 15. Reject H0 if tcalc < -1.740

(b)

If = 0.01, we would have

rejected the null hypothesis. ( calculated P value 0.004 < 0.01 level)

failed to reject the null hypothesis.

(c)

Use Excel to find the p-value. (Round your answer to 4 decimal places.)

  p-value =0.0040

The average weight of a package of rolled oats is supposed to be at least 15 ounces. A sample of 18 packages shows a mean of 14.71 ounces with a standard deviat
The average weight of a package of rolled oats is supposed to be at least 15 ounces. A sample of 18 packages shows a mean of 14.71 ounces with a standard deviat
The average weight of a package of rolled oats is supposed to be at least 15 ounces. A sample of 18 packages shows a mean of 14.71 ounces with a standard deviat

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