A pebble of mass 050g is stuck on the wheel of a bicycle mar

A pebble of mass 0.50g is stuck on the wheel of a bicycle, marking a spot on the tire. When the pebble reaches the apex of its path, it is moving 10 mph relative to the axle. The radius of the tire is 8in. What are the linear momentum and angular momentum about the wheel axle for the pebble?

Solution

10 mph=4.4704 m/s

8 inc =.2032 m

linear momentum p = mv = .50g * 4.4704m/s = 2.2352 g·m/s
L = I = (mr²)(v/r) = mvr = .50g * 4.4704m/s * 0.2032m = .454 g·m²/s