H 70 ft as shown in the figure The best view of the target

(H = 70 ft) as shown in the figure. The best view of the target is when theta is maximum. Write a MATLAB program that determines the distance x at which when theta is maximum. Define a vector x with elements ranging from 50 to 1500 with spacing of 0.5. Use this vector to calculate the corresponding values of theta. Then use MATLAB\'s built-in function max to find the value of x that corresponds to the largest value of theta.

Solution

H = 70;
k = 300; %assumption since not given in the problem
thetas = zeros(2901); %create a vector of 2901 elements
M = 0; %initialise maximum
for x=50:0.5:1500
    a = acot(x/k); %calculation of a using geometry
    b = acot(x/(k-H)); %calculation of b using geometry
    theta = a-b;
    if theta>M
        M = theta; %updating maximum
    end
    thetas(int32((x-50)*2+1)) = theta; %adding value to the vector of thetas
end
disp(M); %displaying maximum value