a software company bids on two contracts simultaneously it a
a software company bids on two contracts simultaneously. it anticipates a profit of $120,000 on the larger contract and a profit of $75,000 on the smaller contract. The company estimates there is a 30% chance it will get the larger contract. There is a 70% chance that the company will also win the smaller contract if it wins the larger contract. The company estimates that there is a 60% chance that it will get the smaller contract if it did not get the larger contract. Find the company\'s expected profit and its standard deviation.
Solution
Thus there are 4 possibilities
Expected value of profit = sum of prob x profit
=[ 0.3(120000)+0.7(75000)+0.333(75000)]/2
= 36000+17500+25000/2
= 39225
For variance first find out E(X^2)
= 1/4[0.3(120000)^2+0.7(75000)^2+0.333(75000)^2]
= 1000000/4[4320+1312.5+1875]
= 1876875000
Var(x) = 1876875000-392252
= 338274375
STd dev = 18392.23
| Larger | Smaller contract | ||
| Profit | 120000 | 75000 | |
| Prob | 0.3 | 0.21/0.63=0.333 | |
| prob not | 0.7 | 0.42/0.63=0.667 |
