3 Complete the following exercises a Supppose you survey 50
3. Complete the following exercises:
a) Supppose you survey 50 fellow students and find the following responses concerning their estimate of the cost of a four-year education at a private school. Calculate the mean, median mode and standard deviation. What does this tell you about the shape of the distribution?
b) Assuming the price of hotel rooms are normally distributed, with a mean of $175 and a SD = $50, what would be the price of a room, if only 2.5% of the rooms were more expensive (Hint: Z-Scores)
Solution
Occurance(X)
Frequency(f)
Freq*X
(X-mean)
(X-mean)2
f*(X-mean)2
38000
6
228000
-12000
144000000
864000000
43000
8
344000
-7000
49000000
392000000
48000
12
576000
-2000
4000000
48000000
53000
12
636000
3000
9000000
108000000
58000
8
464000
8000
64000000
512000000
63000
4
252000
13000
169000000
676000000
Total ->
50
2500000
-
-
2600000000
Answer:
Mean = 50000
Standard Deviation = 7284.314
Variance = 53061224.49
Mode = 46-50 and 51-55 (in 000s)
Median = 25 lies in 46-50000
Hence median = 48000
The frequency increases reaches its peak and decreases.
Hence bell shaped distribution.
---------------------------------------------------------
Normal distribution with mu =175 and sigma = 50
only 2.5% are more expensive
i.e.P(Z>z) = 0.025
z=1.96
x = Mean + 1.96 sigma
= 175+50(1.96)
=175+98
= 273
Hence price of the room = 273
| Occurance(X) | Frequency(f) | Freq*X | (X-mean) | (X-mean)2 | f*(X-mean)2 |
| 38000 | 6 | 228000 | -12000 | 144000000 | 864000000 |
| 43000 | 8 | 344000 | -7000 | 49000000 | 392000000 |
| 48000 | 12 | 576000 | -2000 | 4000000 | 48000000 |
| 53000 | 12 | 636000 | 3000 | 9000000 | 108000000 |
| 58000 | 8 | 464000 | 8000 | 64000000 | 512000000 |
| 63000 | 4 | 252000 | 13000 | 169000000 | 676000000 |
| Total -> | 50 | 2500000 | - | - | 2600000000 |

