A sample of an ideal gas has a volume of 360 L at 1260 C and

A sample of an ideal gas has a volume of 3.60 L at 12.60 °C and 1.40 atm. What is the volume of the gas at 21.40 °C and 0.998 atm?

Solution

As

P1 V1 / T1 = P2 V2 /T2

Then, as T1 = 12.60 C = 285.75 K, T2 = 21.40 C = 294.55 K, then

V2 = P1 V1 T2 / (T1 P2)

V2 = (1.40 atm)(3.60 L)(294.55 K) / [(285.75 K)(0.998 atm)]

= 5.21 L [ANSWER]