cos tan 1 inverse 34 tan1 inverse 158Solutioncos tan1 34

cos ( tan -1 inverse (- 3/4) - tan-1 inverse (-15/8)

cos ( tan^-1 (-3/4) - tan^-1 (-15/8))

tan^-1 {(a-b) / 1+ab)} = tan^-1 { ( -3/4 +15/8) / 1+ (-3/4)(-15/8) = tan^-1 (3/8/ 77/32) = tan^-1 ( 12/77)

cos ( tan^-1 12/77)

let ( tan^-1 12/77) = x

tan x = 12 / 77

cos x = 77 / 78

therefore, cos ( tan -1 (- 3/4) - tan-1 (-15/8) = 77/78

$cos ( tan -1 inverse (- 3/4) - tan-1 inverse (-15/8)Solutioncos ( tan^-1 (-3/4) - tan^-1 (-15/8)) tan^-1 {(a-b) / 1+ab)} = tan^-1 { ( -3/4 +15/8) / 1+ (-3/4)(-1$

cos tan 1 inverse 34 tan1 inverse 158Solutioncos tan1 34

Solution

Get Help Now

Submit a Take Down Notice