PLEASE DO ALL THREE Find the orbit under the sum of proper

PLEASE DO ALL THREE !!!

Find the orbit under the sum of proper divisors function of the numbers 124 111 129

Solution

1) Step 1: Find the proper divisors of the function

First factor the function

124 = 2 X 2 X 31

Hence the factors are 1,2,4,31,62

Orbit number (124) = sum of all proper divisors

=> 1 + 2 + 4 + 31 + 62

=> 100

2) First factor the number

111 = 3 * 37

Hence the factors are 1,3,37

Orbit number (111) = sum of all proper divisors

=> 1 + 3 + 37

=> 41

3) 129

129 = 3 * 43

Hence the factors are 1,3,43

Orbit number (129) = sum of all proper divisors

=> 1 + 3 + 43

=> 47