When looking at the top of a building 300 m away the angle b

When looking at the top of a building 300 m away, the angle between the top of the building and your eye level is 31°. If your eyes are 1.5 m above the ground, how tall is the building?

Solution

d = 300 m

the angle between the top of the building and your eye level = 31 degree

Distance of top of building from eyes = S = 300/sin31 = 582.48 m

Length of building L = 582.48*cos31 + 1.5 = 500.78 m