Determine whether the improper integral converges or diverge
Determine whether the improper integral converges or diverges. If the integral converges, evaluate its value.
a)
b)
Solution
a)
=x-0.9+1/(-0.9+1)=x0.1/(0.1) |0..1=1
so it converges to 1
b)
=ln(x2+1)|1..=-ln(2)=
so it diverges
the integral can be done directly (the derivative of ln(x2+1) is 2x/(x2+1))
