Determine whether the improper integral converges or diverge

Determine whether the improper integral converges or diverges. If the integral converges, evaluate its value.

a)


b)


Solution

a)
=x-0.9+1/(-0.9+1)=x0.1/(0.1) |0..1=1

so it converges to 1

b)

=ln(x2+1)|1..=-ln(2)=

so it diverges

the integral can be done directly (the derivative of ln(x2+1) is 2x/(x2+1))

Determine whether the improper integral converges or diverges. If the integral converges, evaluate its value. a) b) Solutiona) =x-0.9+1/(-0.9+1)=x0.1/(0.1) |0..

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