Find the equation of the line Through 415 perpendicular to y

Find the equation of the line. Through (4,15); perpendicular to y = 10. The equation is . (Simplify your answer. Type your answer in standard form.)

Solution

Y=10 this indicates that the x term has a zero multiplier.
This slope=0 indicating a horizontal line through y=10.

slope of line perpendicular to given line=0 (negative reciprocal)

equation y = 0x + b

solve for b using coordinates of given point (4,15)

15 = 0(4) + b

=> b = 15

Equation of perpendicular line: y=0x+ 15

y = 15