It is required to install solar photovoltaic module to suppl

It is required to install solar photovoltaic module to supply electricity for a small house in Taif city. The residence devices in the house is shown in the table below. The module characteristics as follows: Nominal output (Pmpp): 280W, 8.5 Amps, 24 V, Max Power Voltage (Ympp): 24.5 Volts, Max Power Current (Impp): 8.9 Amps, Open Circuit Voltage (Voc): 38.9 Volts, Short Circuit Current (Isc): 9.4 Amps The system Voltage is 24 V DC and the battery type and characteristic is as follows: 12 Volt 200Ah Heavy Duty \"Extreme\" battery by VMAXTANKS Dimension: 20.8\"L times 8.7\"W times 9.0\"H (9.8\"h to top of terminals) Terminals Posts: SAE+3/8\" STUD (Posts included) MODOD: 0.7 Bulk charging voltage required: 14.4-14.9V: Float voltage: 13.5V If you know that the minimum peak sun time is 4 hour and autonomy day is 2: Calculate: How many module required, and its combination and parallel ? How many batteries required and what is he combination series and parallel ?

Solution

Energy consumed per week by load of given house is

E = (1*220*2.73*0.3*7) + (1*220*4.55*0.4*3) + (1*220*0.57*3*7) + (15*220*0.045*6*7) + (1*220*0.91*12*7)

        +  (1*220*0.2*12*7) + (2*220*0.57*6*7) + (1*220*1.14*0.5*3) + (1*220*0.4*2*7)

E = 1261.26 + 1201.2 + 2633.4 + 6237 + 16816.8 + 3696 + 10533.6 + 376.2 + 1232 = 43987.46 Wh

    = 43.98746 kWH

Given system battery based system and need consider autonomy for 2 days we need design PV system based on energy consumed by Load and need to store in battery .

Given Peak sun hours per day is = 4 hours which indicates energy from sun is 4 kWh/m² -day

one Peak sun is 1000 W /m² of sun power per second and for 4 hours it will be 4 kWh/m²

Given each module capable of generating peak power of P_mpp = 204 W

Each module can generate energy of 4*(24*8.5) = 0.816 kWH

Average Energy consumed by load per day is = 43.98746 / 7 = 6.284 kWH / day

Total energy need to store in battery per week E_B= (43.98746 + (2*6.284) ) / (0.7)= (56.55546)/(0.7) kWH / week

Total energy need to be generated by PV system per day is E_T= 80.7935 / 7 = 11.5419 kWH

Given per day there are only 4 peak hours and each 280 W module capable of generating energy of 0.816 kWH

No.of Modules required is N = E_T / 1.12 = 11.5419 / 0.816 = 14.140 =~ 14 modules ;

1. )

Total No.of Modules need is 14

If 14 modules considered then 14 modules should be connected in parallel because system voltage is 24 V is which is voltage of each modules at mpp.

2)

No.of batteries required is

Energy stored by one battery is E_B = 12 * 200 = 2.4 kWH

No.of Batteries required to store energy of E_T = 11.5419 / 2.4 = 4.8 =~ 6 batteries need for easy connection in series and parallel

No.of batteries need to be connected in series is = 2

No.of parallel strings of 2 batteries is = 3