Write the partial fraction decomposition of the rational exp
Write the partial fraction decomposition of the rational expression 3x - 26/x^2 - x - 12 4/x - 6 - 2/x + 2 3/x - 3- 2/x - 4 3/x + 3 - 2/x - 4 5/x + 3 - 2/x - 4 2/x + 6 - 5/x - 2
Solution
(3x-26)/(x2-x-12)
=(3x-26)/(x2-4x+3x-12)
=(3x-26)/(x(x-4)+3(x-4))
=(3x-26)/((x+3)(x-4))
let (3x-26)/((x+3)(x-4)) =a/(x+3) +b/(x-4)
(3x-26)/((x+3)(x-4)) =(a(x-4)+ b(x+3))/((x+3)(x-4))
(3x-26)/((x+3)(x-4)) =((a+b)x+(-4a+ 3b))/((x+3)(x-4))
a+b = 3 , -4a+3b =-26
b =3-a
-4a+3(3-a) =-26
-4a+9-3a=-26
7a=35
a=5
b =3-a
b =3-5
b =-2
(3x-26)/((x+3)(x-4)) =5/(x+3) -2/(x-4)
therefore (3x-26)/(x2-x-12) =5/(x+3) -2/(x-4)
