solve 2sin2xsinx10 in both deg and radiansSolution2sin2x sin

solve 2sin^2x-sinx-1=0 in both deg and radians

Solution

2sin²x -sinx-1=0

2sin²x-2sinx +sinx -1=0

2sinx(sin x -1) + 1(sinx-1)=0

(2sinx +1)(sin x-1)=0

sinx=-1/2    and sinx=1

x=sin^-1(-1/2)    and   x=sin^-11

x= -pi/6,pi/2

x=-30 degree and 90 degree