I only need the answers the work does not have to be shown

The position of a particle moving along an x axis is given by x 2112 613, wherexis in meters and t is in seconds (a) Determine the position of the particle at t 3.0 s. 27 (b) Determine the velocity of the particle at t 3.0 s. (Indicate the direction with the sign of your answer.) X m/s 27 (c) Determine the acceleration of the particle at t 3.0 s. (Indicate the direction with the sign of your answer X m/s2 27 (d) What is the maximum positive coordinate reached by the particle? X m 27 (e) At what time is it reached? 27 (f) What is the maximum positive velocity reached by the particle? X m/s 27 (g) At what time is it reached? 27 (h) what is the acceleration of the particle at the instant the particle is not moving (other than at t 0)? (Indicate the direction with the sign of your answer.) X m/s2 (i) Determine the average velocity of the particle between t 0 and t 3 s. (Indicate the direction with the sign of your answer.) 27 x m/s

Solution

b)

V=dX/dt =42t-18t²

at t=3 s

V=42*3-18*9 =-36 m/s

c)

a=dV/dt= 42-36t

a=42-36*3 =-66 m/s²

d)

V=42t-18t²

t=2.33 s

X=21*2.33²-6*2.33³

X=38.11

e)

t=2.33 s

f)

a(t)=42-36t=0

t=1.17 s

V=42*1.17-18*1.17²=24.5 m/s

g)

t=1.17 s

h)

a =42-36*2.33

a=-42 m/s²

i)

a(0) =42-36*0 =42 m/s²

V_avg=-66-42/3-0 =-36 m/s