Consider the given circuit Assume R 2 Find the average pow

Consider the given circuit. Assume R = 2 ?.

Find the average power delivered by the source.

The average power delivered by the source is (_________)W.

Solution

Equivalent impedance:

Zeq=[(8+j6)(10-j5)]/[8+j6+10-j5]=(8.15+j0.7692) ohmss.

current from the source=(50<33)/Zeq.

current from the source= (50<30)/(8.15+j0.7692)=6.1078<27.608 amps.

average power delivered by the source= 50<33*6.1078<27.608

p=305.39 watts.