The reading speed of sixthgrade students is approximately no
Solution
Normal Distribution
 Mean ( u ) =125
 Standard Deviation ( sd )=24
 Normal Distribution = Z= X- u / sd ~ N(0,1)                  
 a)
 P(X < 100) = (100-125)/24
 = -25/24= -1.0417
 = P ( Z <-1.0417) From Standard Normal Table
 = 0.1488                  
 b)
 P(X > 140) = (140-125)/24
 = 15/24 = 0.625
 = P ( Z >0.625) From Standard Normal Table
 = 0.266                  
 c)
 To find P(a < = Z < = b) = F(b) - F(a)
 P(X < 110) = (110-125)/24
 = -15/24 = -0.625
 = P ( Z <-0.625) From Standard Normal Table
 = 0.26599
 P(X < 130) = (130-125)/24
 = 5/24 = 0.2083
 = P ( Z <0.2083) From Standard Normal Table
 = 0.58252
 P(110 < X < 130) = 0.58252-0.26599 = 0.3165                  
 d)
 P(X > 200) = (200-125)/24
 = 75/24 = 3.125
 = P ( Z >3.125) From Standard Normal Table
 = 0.0009                  
 Yes it would unusual as it is below in 5% chance of occuring

