Im having trouble understanding this problem so if you can s

I\'m having trouble understanding this problem so if you can show how you figured out the answer step by step that would be great! thank you :))

Solution

10 .Half life of antibiotic bacteria = T_half = 12 hours

For half life:

y = a (1/2)^t/T_half

a = 10

t = 8hours

y = 10 (1/2) ^8/12 = 10 * (1/2)^0.67

y = 10*0.628 = 6.28 mg

11. By using doubling time concept:

a = 100 pairies dog

After 7 months

y = 200

y = a. 2^7/T_Double

200 = 100* 2^7/T_Double

2 = 2^7/T_Double

T_{Double = 7months}

t = 24 months

y = 100 * 2^24/7

y = 1076.72 mg