Given the following voltage and current it 5 sin377t 40 de

Given the following voltage and current: i(t) = 5 sin(377t - 40 degree)A v(t) = 10 cos(377t + 80 degree)v Determine the phase relationship between i(t) and v(t). v(t) leads i(t) by degrees

Solution

i(t) = 5sin(377t - 40deg)

v(t) = 10cos(377t +80deg) = 10cos(377 - 40deg + 120deg)

Thus v(t) leads i(t) by 120degrees.