In the shown three phase system find the magnitude value of
In the shown three phase system find the magnitude value of the following: The Line Voltages (380 V) The Line Currents (65.8 A)
Solution
EAN= 220 v
EBN= 220<-120
ECN= 220<-240
VAB= line voltage between A and B=EAN+ ENB
= 3*220<30
VBC= line voltage between B and C= 3*220<-90
VCA= 3*220<-210
Magnitude of line voltage= 220*3=381 v
Z=6+8j=10<52
Iab= phase current = VAB/Z= 22*3<-22
Ibc= VBC/z= 3*22<-142
Ica=VCA/z= 3*22<-262
IA= Line current from point A= Iab- Ica=
= 22*3*(1-j*1.36)
Magnitude of line current= |IA|=65.3
