A proton is moving in the x direction with a speed of 479 km

A proton is moving in the -x direction with a speed of 479 km/s through a region containing a uniform 2.12 T magnetic field that points in the -y direction. What is the magnitude of the magnetic force on the proton?

Solution

F = qVB*sin A

F = 1.6*10^-19 C*479*10^3 m/sec * 2.12 T *sin 90

F = 1.62*10^-13 N

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