Researchers sampled 1971 German men to determine if there is

Researchers sampled 1971 German men to determine if there is a relationship between their eye and hair colors. The cross-tabulated results of their sample are given in the contingency table below.


Suppose you randomly select a German man. Find each of the following probabilities.
Note: You can answer as a fraction or in decimal form. Round to 4 decimal places if answering with a decimal.

A) P(red hair):  

B) P(blue eyes):  

C) P(brown hair brown eyes):  

D) P(black hair blue eyes):  

E) P((brown hair)c):  

F) P(brown eyes | red hair):  

G) P((red hair)c | blue eyes):

   Hair Color
Eye Color Brown Black Red Total
Brown 209 511 28 748
Blue 893 300 30 1223
Total 1102 811 58 1971

Solution

a) P(red Hair) = 58/1971 = 0.02942
b) P(Blue Eyes) = 1223/1971 = 0.6205
c) P(brown hair brown eyes) = 893/1971 = 0.45306
d) P(black hair blue eyes) = P(black hair) + P( blue eyes) - P(black hair n blue eyes) = (811+1223 - 300)/1971 = 0.8798

BROWN BLACK RED
BROWN 209 511 28 748 A1
BLUE 893 300 30 1223 A2
Totals 1102 811 58 1971
B1 B2
Researchers sampled 1971 German men to determine if there is a relationship between their eye and hair colors. The cross-tabulated results of their sample are g

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