A mass weighing 4 pounds is attached to a spring whose sprin

A mass weighing 4 pounds is attached to a spring whose spring constant is 25 lb/ft. What is the period of simple harmonic motion? .443 Incorrect: Your answer is incorrect. s

Solution

Period = 1/frequency, frequency = omega/(2*pi)

omega = root(k/m) k = spring constant (25 lb/ft), m = 4 lbs. implies omega = root(25/4) implies omega = 5/2.

frequency = 5/(4*pi) = 0.3978

period = 1/0.3978 = 2.5132 seconds.