URGENT HELP NEEDED Solve this equation for ALL REAL VALUES o

*URGENT HELP NEEDED!* Solve this equation for ALL REAL VALUES of x

sinx + cos²x - 1 = 0

Solution

Solution:- Given sin x +cos² x -1 = 0

sin x + 1 -sin²x -1 =0

sin x - sin²x=0

sin x (1 - sin x) = 0

sin x = 0

x = 0, n pi , where n = 1, 2,3 ....

1 -sin x =0

sin x = 1

x = pi/2 , pi/2 + n pi