Homework Soursegiven the functions fxa2 2ab b2c and gx 3b2c 6ab what is f
given the functions: f(x)=a^2 - 2ab +b^2c and g(x)= -3b^2c + 6ab, what is (f-g)(x)?
given the functions: f(x)=a^2 - 2ab +b^2c and g(x)= -3b^2c + 6ab, what is (f-g)(x)?
given the functions: f(x)=a^2 - 2ab +b^2c and g(x)= -3b^2c + 6ab, what is (f-g)(x)?
Solution
Given that
f(x) = a2 - 2ab + b2c , g(x) = -3b2c + 6ab
(f - g)(x) = f(x) - g(x)
= a2 - 2ab + b2c - ( -3b2c + 6ab )
= a2 - 2ab + b2c + 3b2c - 6ab
= a2 - 8ab + 4b2c
Therefore ,
(f - g)(x) = a2 - 8ab + 4b2c
