if 10 electrical cable has a resistance of 0448 ohms per fo

if # 10 electrical cable has a resistance of 0.448 ohms per foot, what is the maximum length in feet that the cable can be without producig the 5% voltage drop at the compressor? Round to the nearest whole foot

Solution

We assume that the question is about a DC circuit. As per Ohm\'s law, the current through a conductor between two points is directly proportional to the voltage across the two points. In a DC circuit, voltage equals current multiplied by resistance i.e. V=IR. Now, since the current is constant, then the voltage drop at the compressor will be 5 % when R = 0.95 ohm. Further, since the electrical cable has a resistance of 0.448 ohm per foot, the resistance of the cable will be 0.95 ohm when its length is 0.95/0.448 = 2.120535714 feet = 2 feet approximately ( on rounding off to the nearest whole foot).

if # 10 electrical cable has a resistance of 0.448 ohms per foot, what is the maximum length in feet that the cable can be without producig the 5% voltage drop

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