6 6 y 3 21 5 2y55SolutionWe need to solve the equation

6 ( 6 y + 3 ) + 21 = 5 (2y+5)-5

We need to solve the equation

6 ( 6 y + 3 ) + 21 = 5 (2y+5) -5 for y.

Opening parenthesis on both sides, we get

36 y + 18 + 21 = 10y + 25 -5

Combining like terms on both sides, we get

36y +39 = 10y +20

Transposing y-terms on LHS and constants on RHS, we get

36y-10y = 20 - 39

26 y = -19

Dividing both sides by 26, we get

y = -19/26