Determine equations for diameter bisection width arc connect
Determine equations for diameter, bisection width, arc connectivity and cost (number of links) for the following static network topologies: Completely-connected, star, complete binary tree, linear array, ring, 2-D mesh without wraparound, 2-D wraparound mesh and hypercube.
Solution
By definiton the value of these parameters is
Diameter : It is the distance between farthest two nodes in the network. Specifies max number of hops.
Bisection width : It is the minimum number of wires you must cut to divide the network into two equal parts.
Cost : The number of links is a meaningful measure of the cost. However, a number of other factors, such as the ability to layout the network, the length of wires, etc., also factor in to the cost.
Arc Connectivity: he minimum number of links that must be removed to break the network into two disconnected networks, not necessarily equal in size.
| Network | Diameter | BisectionWidth | Arc Connectivity | Cost |
| (No. of links) | ||||
| Completely-connected | 1 | p2/4 | p-1 | p(p-1)/2 |
| Star | 2 | 1 | 1 | p-1 |
| Complete binary tree | 2log((p+1)/2) | 1 | 1 | p-1 |
