An iceberg floats with approximately 17 of its volume in the
An iceberg floats with approximately 1/7 of its volume in the air as is shown in the \"Iceberg\" figure. If the wind velocity is U and the water is stationary, the speed at which the wind forces the iceberg through the water is about:
Hint:
i. Assume the drag coefficients for the exposed and submerged portions are equal.
ii. Take the area ratio of the exposed and submerged portions as the (volume ratio)2/
volume in air volume in waterSolution
Drag=0.5*density*U^2*Cd * Area
the top part of the iceberg experiences a force provided by the wind.
density of air = 1.2 (roughly)
Area=(1/7) * (2/3) = (2/21)
therefore the Drag=(2/35) U^2*Cd (this is the force pushing the iceberg)
The resistive force provided by the water is made from the same drag equation but;
Density=1000
Area=(6/7) * (2/3)
Therefore the resistive force = (914/21) U^2 * Cd
Divide the pushing force by the resistive force and we arrive at 0.002 U answer
