QUESTION 1 What is the index number of the last component in

QUESTION 1

What is the index number of the last component in the array numList above?

int numList[50];

for (int i = 0; i < 50; i++)
numList[i] = 2 * i;

numList[10] = -20;
numList[30] = 8;

0

49

30

50

QUESTION 2

What is the value of numList length (size) in the last question?

0

49

30

50

QUESTION 3

Consider the following statements:

int hits[] = {5, 7, 9, 11, 13, 15};

What is the number of elements in the array hits.

0

6

5

15

QUESTION 4

Complete the following C++ program that prints the content of a string in the reverse order
  
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
char str[] = “CSE 100 Fall 2014”;
  
/* To Do: Select a for loop that prints the content of the string in the reverse order
Hint: you can use strlen( const char* ) function to get the length of the string
    Ex. char str[] = \"Cat\"; int length; length = strlen(str); length gets 3.
*/

return 0;
}

int i, length;

length = strlen(str);

for(i=0;i<length;i++){

   cout<<str[i];

}

cout<<endl;

int i, length;

length = strlen(str);

for(i=length-1;i>=0;i--){

   cout<<str[i];

}

cout<<endl;

int i, length;

length = strlen(str);

for(i=length-1;i>=0;i++){

   cout<<str[i];

}

cout<<endl;

int i, length;

length = strlen(str);

for(i=length;i>0;i--){

   cout<<str[i];

}

cout<<endl;

		0
		49
		30
		50

Solution

Ans)

Question 1) 49

Indexing of array starts from 0,1,2,3 ...so on,So for a array size of 50 the index count is from 0 to 49

so the index number of last component in the array numList is 49

----------------------------------

Question2) 50

The array size is no of element it can store or no of memory locations ,as numlist is defined as numList[50]

it can store 50 elements ,so its size is 50

-----------------------------------------

Question3) 6

Count the no of elements starting from 1 and there are 6 elements

Only 1question per post will be answered but I answerd 3 here