area of the curve ylnx between y1 and y2 and x0 rotated abou

area of the curve y=lnx between y=1 and y=2 and x=0 rotated about the y axis

Hi,

e^y = e^(lnx)
e^y = x
x = e^y

Now, take the integral:

int 1 to 2 (e^y)² dy = 23.604546967 = 74.155871343

area of the curve y=lnx between y=1 and y=2 and x=0 rotated about the y axisSolutionHi, ey = e(lnx) ey = x x = ey Now, take the integral: int 1 to 2 (ey)2 dy =

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