There is a 01019 probability that a bestofseven contest will
     There is a 0.1019 probability that a best-of-seven contest will last four games, a 0.1853 probability that it will last five games, a 0.1897 probability that it will last six games, and a 0.5231 probability that it will last seven games. Verify that this is a probability distribution. Find its mean and standard deviation. Is it unusual for a team to \"sweep\" by winning in four games?  What is the mean of the probability distribution?  What is the standard deviation of the probability distribution?  Is it unusual for a team to win in four games? Choose the correct answer below.  Yes, because the probability that a team wins in four games is greater than 0.05.  No. because the probability that a team wins in four games is less than or equal to 0.05.  Yes, because the probability that a team wins in four games is less than or equal to    
 
  
  Solution
Consider:
a)
Thus,          
           
 E(x) = Expected value = mean =    6.134 [ANSWER]
b)
Var(x) = E(x^2) - E(x)^2 = 1.098044
Thus,
s(x) = sqrt [Var(x)] = 1.047875947 [ANSWER]
c)
NO, becasue the probability of winning in four games is greater than 0.05.
| x | P(x) | x P(x) | x^2 P(x) | 
| 4 | 0.1019 | 0.4076 | 1.6304 | 
| 5 | 0.1853 | 0.9265 | 4.6325 | 
| 6 | 0.1897 | 1.1382 | 6.8292 | 
| 7 | 0.5231 | 3.6617 | 25.6319 | 

