Calculate the mean and standard error for the following samp
Calculate the mean and standard error for the following sample, 32, 39, 30, 53, 28, 30, 30, 46, 45. Is the null hypothesis of the true mean 90 true or false according to a one-tailed t-test assuming the sample\'s mean is greater than the null hypothesis with an alpha level of 0.05. Tip: once you enter in data for the y, use the following R comand: t.test(y.A, mu =90, alternative = alternativeoption), where alternativeoption is either two.sided, greater, or less (in quotes), depdending on the question text.
True or False?
Solution
3.02306
Null hypothesis: the populaiton mean 90
alternative hypothesis: mean is greater than 90
test statistic is t = (sample mean- populaiton mean)/SE = (37-90)/3.02306 = -17.53
P-value is one.
so accept the null hypothesis. the populatin mean is 90
| x | (x-mean)^2 |
| 32 | 25 |
| 39 | 4 |
| 30 | 49 |
| 53 | 256 |
| 28 | 81 |
| 30 | 49 |
| 30 | 49 |
| 46 | 81 |
| 45 | 64 |
| 333 | 658 |
