Suppose X and Y are random variables with EX 2 EY 3 VarX
Suppose X and Y are random variables with E(X) = 2, E(Y) = 3, Var(X) = 4, Var(Y) 10, and Cov(X, Y) =-5 Find Var(5X + 2Y) Find Cov(3X + Y, Y).
Solution
a)VAR(5X+2Y) = 5VAR(X) + 2VAR(Y)
VAR(X) = 4, VAR(Y) = 10
5*4+2*10 = 20+20 = 40
B)COV(3X+Y,Y) =
COV(3X,Y) + COV(Y,Y)
NOW COV(Y,Y) = (VAR(Y,Y) = 10
ALSO COV(X,Y) = -5
SO COV(3X,Y) = 3COV(X,Y)
= 3*-5 = -15
HENCE THE ANSWER WILL BE
-15+10 = -5
