To investigate the fluid mechanics of swimming twenty swimme
Solution
Set Up Hypothesis
 Null Hypothesis , There Is No-Significance between them Ho: u1 = u2
 Alternate Hypothesis, There Is Significance between them - H1: u1 != u2
 Test Statistic
 X(Mean)=1.477
 Standard Deviation(s.d1)=0.339 ; Number(n1)=20
 Y(Mean)=1.434
 Standard Deviation(s.d2)=0.333; Number(n2)=20
 we use Test Statistic (t) = (X-Y)/Sqrt(s.d1^2/n1)+(s.d2^2/n2)
 to =1.477-1.434/Sqrt((0.11492/20)+(0.11089/20))
 to =0.4
 | to | =0.4
 Critical Value
 The Value of |t | with Min (n1-1, n2-1) i.e 19 d.f is 2.861
 We got |to| = 0.40468 & | t  | = 2.861
 Make Decision
 Hence Value of |to | < | t  | and Here we Do not Reject Ho
 P-Value: Two Tailed ( double the one tail ) - Ha : ( P != 0.4047 ) = 0.69
 Hence Value of P0.01 < 0.69,Here We Do not Reject Ho
ANS:
t = 0.4
df = 19
P = 0.69
No

