In the week before and the week after aholiday there were 10

In the week before and the week after aholiday, there were 10,000 total death and 4994 of them occurred in the week before the holiday.

a. Construct a 90% confidence interval estimate of the proportion of deaths in the week before the holiday to the total deaths in the week before and the week after the holiday.

b. Based on theresult, does there appear to be any indication that people can temporarily postpone their death to survive theholiday?

Solution

Confidence Interval For Proportion
CI = p ± Z a/2 Sqrt(p*(1-p)/n)))
x = Mean
n = Sample Size
a = 1 - (Confidence Level/100)
Za/2 = Z-table value
CI = Confidence Interval
Mean(x)=4994
Sample Size(n)=10000
Sample proportion = x/n =0.499
Confidence Interval = [ 0.499 ±Z a/2 ( Sqrt ( 0.499*0.501) /10000)]
= [ 0.499 - 1.64* Sqrt(0) , 0.499 + 1.64* Sqrt(0) ]
= [ 0.491,0.507]