fx 2x2x2logx find least integer nSolutionAnswer fx 2x2 x2l
f(x)= 2x^2+x^2logx find least integer n
Solution
Answer:
f(x) = 2x^2 + x^2logx < = x^n
=> x^2( 2 + logx) < = x^n
=> x^2 = x^n
log x^2 = logx^n
=> 2logx = nlogx => n = 2
Therefore n = 2

f(x)= 2x^2+x^2logx find least integer n
Answer:
f(x) = 2x^2 + x^2logx < = x^n
=> x^2( 2 + logx) < = x^n
=> x^2 = x^n
log x^2 = logx^n
=> 2logx = nlogx => n = 2
Therefore n = 2
