fx 2x2x2logx find least integer nSolutionAnswer fx 2x2 x2l

f(x)= 2x^2+x^2logx find least integer n

Solution

Answer:

f(x) = 2x^2 + x^2logx < = x^n

=> x^2( 2 + logx) < = x^n

=> x^2 = x^n

log x^2 = logx^n

=> 2logx = nlogx => n = 2

Therefore n = 2

f(x)= 2x^2+x^2logx find least integer nSolutionAnswer: f(x) = 2x^2 + x^2logx < = x^n => x^2( 2 + logx) < = x^n => x^2 = x^n log x^2 = logx^n => 2

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