For this assignment your program must read in data from an i

For this assignment, your program must read in data from an input File called \"input.txt\", verify that the given number and \"source base\" have the appropriate digits, perform the conversion, and write the converted number or error message to the output File called \"output\". If a number in the input File contains an inappropriate digit, your program should print an error message to the File, and go to the next number to convert You will need to create your own \"input.txt\" File to test your program. Your program must include three functions to perform the following tasks. Check that a given number is in the correct base. Your function should check if the input number of the proper base. Your function will take two inputs: the number to check and its base. Your function should return a Boolean variable, i.e., true or false. Here are a few examples: Convert from base-2 to base-10. Convert from base-10 to

Solution

#include<iostream>
#include <fstream>
using namespace std;
bool checkBase(int num, int base);
int convert2To10(int num);
int convert10To2(int num);
int main()
{
ifstream fin; //Read file
ofstream fou; //Write file
int num, base, base2, base10;
char underscore;
bool res;
fin.open(\"input.txt\"); //Open input.txt file for reading
fou.open (\"output.txt\"); //Open output.txt file for writing
while (!fin.eof()) //Checks end of file
{
fin>>num>>underscore>>base; //Reads the first data
res = checkBase(num, base); //Checks the correct base
//If base is correct and it is 10 convert it into base 2
if(res == true && base == 10)
{
//Writes to the output.txt file
fou<<\"\ decimal = \"<<num<<\" binary = \"<<convert10To2(num)<<endl;
}
//If base is correct and it is 2 convert it into base 10
else if (res == true && base == 2)
{
//Writes to the output.txt file
fou<<\"\ binary = \"<<num<<\" decimal = \"<<convert2To10(1001);
}
else
//Incorrect base Error is written onto the file
fou<<\"\ Wrong base \";
}
}
//Converts base 2 to base 10
int convert2To10(int num)
{
int rem, bin, dec = 0, base = 1;
bin = num;
while (num > 0)
{
rem = num % 10;
dec = dec + rem * base;
base = base * 2;
num = num / 10;
}
return dec;
}
//Converts base 10 to base 2
int convert10To2(int dec)
{
int rem, sum = 0, i = 1;
do
{
rem=dec%2;
sum=sum + (i*rem);
dec=dec/2;
i=i*10;
}while(dec>0);
return sum;
}

//Checks for the correct base
bool checkBase(int no, int ba)
{
int f = 0, r;
if(ba == 2)
{
while(no > 0)
{
r = no % 10;
if(r == 0 || r == 1)
{
no = no / 10;
}
else
{
f = 1;
break;
}

}
if(f == 1)
return false;
else
return true;
}
if(ba == 10)
{
while(no > 0)
{
r = no % 10;
if(r == 0 || r == 1 || r == 2 ||r == 3 ||r == 4 ||r == 5 ||r == 6 ||r == 7 ||r == 8 ||r == 0)
{
no = no / 10;
}
else
{
f = 1;
break;
}
}
if(f == 1)
return false;
else
return true;
}

}

Input File:

1001, 2
1001, 10
12301, 2
12801, 10

Output File:

binary = 1001 decimal = 9
decimal = 1001 binary = 1111101001

Wrong base
decimal = 12801 binary = 1588754945