Solve the triangle with a 12m b 31m and A 205 degrees If the

Solve the triangle with a= 12m, b= 31m and A= 20.5 degrees. If there is more than one triangle, find them both. Round decimals answers to the nearest tenth.

apply sine rule to find angle B:

a/sinA = b/sinB

sinB = b*sinA/a = 31*sin20.5/12 = 0.9047

B1 = 64.78 deg ; B2 = 180 - 64.78 = 115.22 deg

C1 = 180 - 20.6 -64.78 = 94.62 deg ; C2 = 44.28 deg

Now we can see we have two triangles with AB1C1 and AB2C2

Lets find c1 and c2:

c1/sinC1 = a/sinA

c1 = sin94.62*12/sin20.5 = 34.15 m

c2 = sinC2*a/sinA = sin44.28*12/sin20.5 = 23.92 m

So, we have all sides and angles of both triangles

Solve the triangle with a= 12m, b= 31m and A= 20.5 degrees. If there is more than one triangle, find them both. Round decimals answers to the nearest tenth. So

Solve the triangle with a 12m b 31m and A 205 degrees If the

Solution

Get Help Now

Submit a Take Down Notice