Eight players play a card game with a 52 card deck The deck
Eight players play a card game with a 52 card deck. The deck is shuffled and each player is dealt four cards.
a.) What is the probability that player A gets all four kings?
b.) What is the probability that some player gets all four kings?
c.) What is the probability that player A gets four cards of a kind? (That is, four aces, four kings, four queens, ... four aces.)
d.) What is the probability that some player gets four cards of a kind? Why is it a lot harder to go from answer c. to answer d. than it was to go from answer a. to answer b.?
Solution
8 players, each getting 4 cards
So, 32 cards will be dealt in all
To get all the four kings, one must ensure that the deck has all the four kings,
the sample would be number of ways of choosing 28 cards from 48 and the four kings = 48C28
The number of ways in which the four kings can be given to a specific player = 1
Thus, required probability
= 1 / 48C28
b) If one of the 8 players is to get the four kings, the probability just gets multiplied by 8
Hence the required probability = 8 / 48C28
c) This part gets more complex.
The denominator here = 52C32
The problem is that there might be more than one four of kind in the 32 cards thus selected
Also, it is difficult to determine which card value is as four of a kind (aces, kings, queens, . , etc...)
Going from C to D is tougher because of the number of permutations increase in number with the changes in the card value as well as the player who gets four of a kind
