In a clinical trial of a drug used to help subjects stop smo

In a clinical trial of a drug used to help subjects stop smoking, 823 subjects were treated with 1 mg doses of the drug. That group consisted of 39 subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.0129.

Assuming that the drug has no effect, so that the probability of nausea was 0.0129, find the mean and standard deviation for the numbers of people in groups of 823 that can be expected to experience nausea.

Solution

Mean ( np ) = 823 * 0.0129 = 10.6167
Standard Deviation ( npq )= 823*0.0129*0.9871 = 3.2372