You crossed PP CC purplestemmed cutleaved tomatoes with pp c

You crossed PP CC (purple-stemmed, cut-leaved) tomatoes with pp cc (green-stemmed, potato-leaved) tomatoes and self-pollinated the F1 to obtain an F2 progeny. In the F2, what proportion of the purple-stemmed and cut-leaved plants were true-breeding?

Solution

Answer:

P1= PPCC x ppcc

F1= PpCc

F2= F1 x F1

PpCc x PpCc

Probability of PPCC: PP=1/4, CC=1/4 =1/16

Purple stemmed cut leaved = are just 1/16


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 You crossed PP CC (purple-stemmed, cut-leaved) tomatoes with pp cc (green-stemmed, potato-leaved) tomatoes and self-pollinated the F1 to obtain an F2 progeny.

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