Write a Python program that counts the number of times each

Write a Python program that counts the number of times each digit occurs, the number of times a whitespace occurs, and the number of other characters.

It returns a list of 12 elements (a count for each of the ten digits, plus whitespace, plus other characters).

It is possible to write it in two lines of code, but not required

def mycount(str):

mycount = [ str.count(c) for c in \"0123456789 \\t\ \" ]

return

Solution

def mycount(str):
   count = [0,0,0,0,0,0,0,0,0,0,0,0]
   for i in range(len(str)):
       # if str[i] is digit, increment count of that index.
       if(str[i].isdigit()):
           count[int(str[i])] += 1
       elif(str[i]==\" \"):
           count[10] += 1
       else:
           count[11] += 1
   return count
print mycount(\"123ljkf567abc\ \")

\"\"\"
sample output

[0, 1, 1, 1, 0, 1, 1, 1, 0, 0, 0, 8]
\"\"\"