Consider the function Fx 2xx123 Find the volume of the soli
Consider the function F(x) = ((2x)(x^1/2))/3
Find the volume of the solid obtained by rotating the region between F(x) and y= 0 about the line y=-1 over the interval [0,3].
Find the volume of the solid obtained by rotating the region between F(x) and y= 0 about the line y=-1 over the interval [0,3].
Solution
we use disk method
r2 dx
the radius r=F(x)+1
So the integral is
03(2xx/3+1)2 dx
=034/9x3+4xx/3+1 dx
=...=(12+243/5)
