Consider the function Fx 2xx123 Find the volume of the soli

Consider the function F(x) = ((2x)(x^1/2))/3
Find the volume of the solid obtained by rotating the region between F(x) and y= 0 about the line y=-1 over the interval [0,3].

Solution

we use disk method

r2 dx

the radius r=F(x)+1

So the integral is

03(2xx/3+1)2 dx

=034/9x3+4xx/3+1 dx

=...=(12+243/5)

Consider the function F(x) = ((2x)(x^1/2))/3 Find the volume of the solid obtained by rotating the region between F(x) and y= 0 about the line y=-1 over the int

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