Calculate the net force magnitude and direction on the charg

Calculate the net force (magnitude and direction) on the charge q_2 in the diagram shown.

Solution

Force on q2 due to charge q1 is F = Kq1q2/(10cm) ²

Where K = Coulomb\'s constant = 8.99 x10 ⁹ Nm ²/C ²

Substitute values you get F =(8.99 x10 ⁹)(2x10 ^-6)(2 x10 ^-6 )/(0.1) ²    Since 10 cm = 0.1 m

                                        = 3.596 N

It is along left side.

Force on q2 due to charge q3 is F \' = Kq1q3/(25cm) ²

Where K = Coulomb\'s constant = 8.99 x10 ⁹ Nm ²/C ²

Substitute values you get F =(8.99 x10 ⁹)(2x10 ^-6)(6 x10 ^-6 )/(0.25) ²    Since 25 cm = 0.25 m

                                        = 1.72608 N

It is along right side.

Net force on q2 due to charges q1 and q3 is F \" = F - F \'

                                                                     = 3.596 N - 1.72608 N

                                                                     = 1.86992 N

Direction:along left side