The city of Tucson Arizona employs people to assess the valu
The city of Tucson, Arizona, employs people to assess the value of homes for the purpose of establishing real estate tax. The city manager sends each assessor to the same five homes and then compares the results. The information is given below, in thousands of dollars. Can we conclude that there is a difference in the assessors, at = 0.05? Assessor Home Zawodny Norman Cingle Holiday A $59 $52 $44 $43 B 59 55 56 56 C 47 54 47 53 D 73 64 61 63 E 82 83 94 86
Is there a difference in the treatment means, at = .05? (Round your answer to 2 decimal places.)
Is there a difference in the block means, at = .05? (Round your answer to 2 decimal places.)
| (a) | Is there a difference in the treatment means, at = .05? (Round your answer to 2 decimal places.) |
Solution
Sol)
Ho: all the Five treatment means are equal
H1: All the five group treatment means are different
Level of significance: 5%
Test statistic:
We Use One way ANOVA (F test)
From Excel
From above analysis
F cal=33.94
and P value=0.000000236
Conclusion: P value < 0.05 , we reject the null hypothesis. Hence the results are significant at 5% level
| Anova: Single Factor | ||||||
| SUMMARY | ||||||
| Groups | Count | Sum | Average | Variance | ||
| A | 4 | 198 | 49.5 | 56.33333 | ||
| B | 4 | 226 | 56.5 | 3 | ||
| C | 4 | 201 | 50.25 | 14.25 | ||
| D | 4 | 261 | 65.25 | 28.25 | ||
| E | 4 | 355 | 88.75 | 52.91667 | ||
| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | P-value | F crit |
| Between Groups | 4202.7 | 4 | 1050.675 | 33.9475 | 2.36E-07 | 3.055568 |
| Within Groups | 464.25 | 15 | 30.95 | |||
| Total | 4666.95 | 19 |
