Encrypt the message HALT by translating the letters into n
Encrypt the message \" HALT \" by translating the letters into numbers
(via A=0,B=1,C=2,D=3,E=4,F=5,G=6,H=7,I=8,
J=9,K=10,L=11,M=12,N=13,O=14,P=15,Q=16,R=17,
S=18,T=19,U=20,V=21,W=22,X=23,Y=24,Z=25 )
and then applying the encryption function given, and then translating the numbers back into letters.
(a) f(p)=(p+5) mod 26 _____________
(b) f(p)=(p+12) mod 26 _______________
(c) f(p)=(p+4) mod 26 ______________
Solution
Encrypt message as : A=0,B=1,C=2,D=3,E=4,F=5,G=6,H=7,I=8,
J=9,K=10,L=11,M=12,N=13,O=14,P=15,Q=16,R=17,
S=18,T=19,U=20,V=21,W=22,X=23,Y=24,Z=25
and given encryption function :a) f(p)=(p+5)mod26 if p=Z=25
f(25)=(25+5)mod26
=30mod26=4
f(25)=E
and f(p)=(p+5)mod26 if p=15
f(15)=(15+5)mod26
=20mod26=20
f(15)=U
b) f(p)=(p+12)mod26
f(p)=(p+12)mod26 if p=Z=25
f(25)=(25+12)mod26
=37mod26=11
f(25)=L
and for f(p)=(p+12)mod26 if p=15
f(15)=(15+12)mod26
=27mod26=1
f(15)=B
c)f(p)=(p+4)mod26
f(p)=(p+4)mod26 if p=Z=25
f(25)=(25+4)mod26
=29mod26=3
f(25)=D
and for f(p)=(p+4)mod26 if p=15
f(15)=(15+4)mod26
=19mod26=19
f(15)=T

