Suppose that sin theta 1213 and 0 Solution0

Suppose that sin theta = 12/13 and 0

Solution

0<</2

0</2</4

sin=12/13

cos=(13²-12²) /13 =5/13

cos(/2) =[(1+cos)/2]

co(/2) =[(1+(5/13))/2]

cos(/2) =(18/26)

cos(/2) =3/13

sin(/2) =[(1-cos)/2]

sin(/2) =[(1-(5/13))/2]

sin(/2) =(4/13)

sin(/2) =2/13

tan(/2) =sin(/2)/cos(/2)

tan(/2)=(2/13)/(3/13)

tan(/2)=2/3