Find the equation of the plane determined by the three point

Find the equation of the plane determined by the three points P(1, 0, -1), Q (2, 2, 1) and R (4, 1, 2) please

Direction vector from point P(1, 0, -1), Q (2, 2, 1) : ( 1, 2, 2)

Direction vector from point P(1, 0, -1) ,R (4, 1, 2) : ( 3 , 1 , 3)

Cross product of two vectors above : ( 1, 2, 2) x ( 3 , 1 , 3) = ( 4, 3, -5)

Taking point ( 1, 0, -1)

Equation of Plane : 4*(x-1) + 3(y -0) -5( z+1) =0

4x -4 +3y -5z -5 =0

4x +3y -5z = 9 (Equation Of Plane