Train A is traveling at 60 mph and train B is traveling 80 m

Train A is traveling at 60 mph and train B is traveling 80 mph. Train A passes a station at 9:10 pm. If train B passes the same station at 9:25 pm, at that time will train B catch up to train A?

Solution

60T=80(T-.25)
60T=80T-20
60T-80T=-20
20T=20
T=20/20
T=1 HOUR AFTER TRAIN A LEAVES THEY WILL MEET.
9:10+1:00=10:10 TIME OF THEIR MEETING.
PROOF:
60*1=80(1-.25)
60=80*.75
60=60